Liudolf (Friesland)

Liudolf, Margrave of Frisia - Margrave of Frisia, Count of Brunswick. Article “Liudolf (Friesland)” in German Wikipedia has 2.7 points for quality (as of July 1, 2025). The article contains 0 references and 2 sections.

This article has the best quality in Greek Wikipedia. However, the most popular language version of this article is English.

Since the creation of article “Liudolf (Friesland)”, its content was written by 28 registered users of German Wikipedia and edited by 128 registered Wikipedia users in all languages.

The article is cited 21 times in German Wikipedia and cited 198 times in all languages.

The highest Authors Interest rank from 2001:

• Local (German): #51032 in April 2018
• Global: #134599 in April 2008

The highest popularity rank from 2008:

• Local (German): #135994 in October 2017
• Global: #351000 in October 2017

There are 9 language versions for this article in the WikiRank database (of the considered 55 Wikipedia language editions).

The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).

The table below shows the language versions of the article with the highest quality.

#	Language	Quality grade	Quality score
1	Greek (el) Λιούντολφ της Φρισίας		30.4399
2	Russian (ru) Людольф (граф Брауншвейга)		22.2056
3	English (en) Liudolf, Margrave of Frisia		20.5415
4	Italian (it) Liudolfo di Frisia		16.3914
5	Dutch (nl) Liudolf van Brunswijk		12.4317
6	French (fr) Liudolf (margrave de Frise)		10.674
7	Bulgarian (bg) Людолф (Фризия)		5.2372
8	German (de) Liudolf (Friesland)		2.7284
9	Japanese (ja) リウドルフ (フリースラント辺境伯)		2.3566

More...

The following table shows the most popular language versions of the article.

The most popular language versions of the article "Liudolf (Friesland)" in all the time

#	Language	Popularity award	Relative popularity
1	English (en) Liudolf, Margrave of Frisia		62 994
2	German (de) Liudolf (Friesland)		26 648
3	Russian (ru) Людольф (граф Брауншвейга)		21 365
4	Dutch (nl) Liudolf van Brunswijk		15 940
5	French (fr) Liudolf (margrave de Frise)		11 795
6	Japanese (ja) リウドルフ (フリースラント辺境伯)		8 850
7	Italian (it) Liudolfo di Frisia		1 538
8	Bulgarian (bg) Людолф (Фризия)		1 182
9	Greek (el) Λιούντολφ της Φρισίας		85

More...

The following table shows the language versions of the article with the highest popularity in the last month.

The most popular language versions of the article "Liudolf (Friesland)" in June 2025

#	Language	Popularity award	Relative popularity
1	English (en) Liudolf, Margrave of Frisia		429
2	German (de) Liudolf (Friesland)		90
3	Russian (ru) Людольф (граф Брауншвейга)		85
4	French (fr) Liudolf (margrave de Frise)		80
5	Dutch (nl) Liudolf van Brunswijk		46
6	Japanese (ja) リウドルフ (フリースラント辺境伯)		43
7	Italian (it) Liudolfo di Frisia		22
8	Bulgarian (bg) Людолф (Фризия)		6
9	Greek (el) Λιούντολφ της Φρισίας		5

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The following table shows the language versions of the article with the highest Authors’ Interest.

Language versions of the article "Liudolf (Friesland)" with the highest Authors Interest (number of authors). Only registered Wikipedia users were taken into account.

#	Language	AI award	Relative AI
1	German (de) Liudolf (Friesland)		28
2	English (en) Liudolf, Margrave of Frisia		28
3	Dutch (nl) Liudolf van Brunswijk		26
4	French (fr) Liudolf (margrave de Frise)		17
5	Italian (it) Liudolfo di Frisia		9
6	Russian (ru) Людольф (граф Брауншвейга)		8
7	Japanese (ja) リウドルフ (フリースラント辺境伯)		6
8	Bulgarian (bg) Людолф (Фризия)		4
9	Greek (el) Λιούντολφ της Φρισίας		2

More...

The following table shows the language versions of the article with the highest Authors’ Interest in the last month.

Language versions of the article "Liudolf (Friesland)" with the highest AI in June 2025

#	Language	AI award	Relative AI
1	Greek (el) Λιούντολφ της Φρισίας		1
2	Bulgarian (bg) Людолф (Фризия)		0
3	German (de) Liudolf (Friesland)		0
4	English (en) Liudolf, Margrave of Frisia		0
5	French (fr) Liudolf (margrave de Frise)		0
6	Italian (it) Liudolfo di Frisia		0
7	Japanese (ja) リウドルフ (フリースラント辺境伯)		0
8	Dutch (nl) Liudolf van Brunswijk		0
9	Russian (ru) Людольф (граф Брауншвейга)		0

More...

The following table shows the language versions of the article with the highest number of citations.

Language versions of the article "Liudolf (Friesland)" with the highest Citation Index (CI)

#	Language	CI award	Relative CI
1	Russian (ru) Людольф (граф Брауншвейга)		35
2	Italian (it) Liudolfo di Frisia		28
3	French (fr) Liudolf (margrave de Frise)		27
4	English (en) Liudolf, Margrave of Frisia		24
5	Dutch (nl) Liudolf van Brunswijk		23
6	German (de) Liudolf (Friesland)		21
7	Bulgarian (bg) Людолф (Фризия)		16
8	Greek (el) Λιούντολφ της Φρισίας		15
9	Japanese (ja) リウドルフ (フリースラント辺境伯)		9

More...

#	Language	Value
bg	Bulgarian Людолф (Фризия)
de	German Liudolf (Friesland)
el	Greek Λιούντολφ της Φρισίας
en	English Liudolf, Margrave of Frisia
fr	French Liudolf (margrave de Frise)
it	Italian Liudolfo di Frisia
ja	Japanese リウドルフ (フリースラント辺境伯)
nl	Dutch Liudolf van Brunswijk
ru	Russian Людольф (граф Брауншвейга)

Best Rank

German: #135994 10.2017

Global: #351000 10.2017

Best Rank

German: #51032 04.2018

Global: #134599 04.2008

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The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information